#4 Left and Right Arrows
Input :7 (Must be odd)
Output:
Program solution for Left Right Arrow
#include <stdio.h>
int main()
{
int i, j, n;
printf("Enter Number: ");
scanf("%d", &n); // ‘n’ must be odd
int num1 = n / 2 * 3;
// right arrow
printf("Right Arrow\n");
for(i = 0; i < n; i++)
{
for(j = 0; j < n; j++)
{
// center horizontal, upper right diagonal, bottom right diagonal
if(i == n / 2 || j - i == n / 2 || i + j == num1)
printf("*");
else
printf(" ");
}
printf("\n");
}
// left arrow
printf("Left Arrow\n");
for(i = 0; i < n; i++)
{
for(j = 0; j < n; j++)
{
// center horizontal, bottom left diagonal, upper left diagonal
if(i == n / 2 || i - j == n / 2 || i + j == n / 2)
printf("*");
else
printf(" ");
}
printf("\n");
}
return 0;
}
